Question

What is the output?
int main()
{
int x = 10;
int y = 20;
if (!(x^y))
printf("O");
else
printf("1");
return 0;
}​

Answer 1

The output of the given condition is 1.

• In this C++ condition we are initializing two integer variables x and y and with values 10 and 20 respectively.
• Then in the 'if' condition we are checking for the negation of x XOR y.
• If the 'if' condition is true we print O.

• Else we print 1.
• Now putting the values of x and y we get x XOR y = 30, which is true in boolean but its negation would be false thus the else part would be printed and that is 1.