Question

What is the output?
main
{
int x=5;
printf("%d", x+++++x);
}​

Answer 1

Explanation:

An output is data that a computer sends. Computers only work with digital information. Any input that a computer receives must be digitised. Often data has to be converted back to an analogue format when it's output, for example the sound from a computer's speakers.

Answer 2

Answer:

The correct output to this question is:  12

Explanation:

Post increment or decrement:

• The assignment is first later the increment or decrement is done to the value

Pre increment or decrement:

• first increment or decrement is done then the final value is assigned to the variable

Given, code snippet is in the c language

main

{

     int x=5;

     printf("%d", x++ + ++x);

}​

According to this code,

1. First, a variable x of datatype integer is declared
2. Next, x is initialized with the value 5
3. In the print statement, the expression consists of the sum of post-increment and pre-increment values of x

x = 5

x ++ = 5   (in this step x = 5 and x is increased by one)

               (now x = 6)

++ x = 7  (in this step x is first increased then assigned)

     

∴ (x ++) + (++ x) = 5 + 7      

x++ + ++x = 12

Hence the final output is 12

Click here for more about increment and decrement:

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Click here for more about post and pre-increment:

https://brainly.in/question/46273957