Question

What is the output of following program?

#include <stdio.h>

int main()

{

    int x = 10, *y, **z;

  

    y = &x;

    z = &y;

    printf("%d %d %d", *y, **z, *(*z));

    return 0;

}

​

Answer 1

Code

Input

#include <stdio.h>

int main()

{

int x = 10, *y, **z;

y = &x;

z = &y;

printf("%d %d %d", *y, **z, *(*z));

return 0;

}

Output

y contains the address of x so *y print 10 then **z contains address of y of x so print the value of x 10 and 3rd *(*z) contains address of y of x that’s why print 10. So, final output is 10 10 10.

Answer 2

ɿᵑᵖᶷᵗ

#include <stdio.h>

int main()

{

    static int i=5;

    if(--i){

        main();

        printf("%d ",i);

    }

}

øᶷᵗᵖᵘᵗ

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