What is the output of the following a
def test func(*a):
print (a [0])
test func (1,2,3,4)
test_func([1,2,3,4])
test func (1)
a) 1[1] 1
b) 111
c)1 [1, 2, 3, 4] 1
d) The code generates an error.
Answers
:::::::def test_func (*a) print (a[0]) test_func1,2,3,4) test func ([1,2,3,4]) test func (1) a) 1 [1] 1 b) 1 11 c) 1 [1, 2, 3, 4] d) The code generates an error. Question.
D) The code contains a syntax error.
The correct code should be:
def test_func(*a):
print(a[0])
test_func(1, 2, 3, 4)
test_func([1, 2, 3, 4])
test_func(1)
Now, the output of the code will be:
1
[1, 2, 3, 4]
1
This is because the function test_func takes a variable number of arguments using the *a syntax.
The code defines a function named test_func that takes a variable number of arguments using the *a syntax. This means that the function can be called with any number of arguments, and they will be collected into a tuple named a.
In the first call to test_func, the arguments (1, 2, 3, 4) are passed, which are collected into a tuple named a. Since a[0] corresponds to the first element of the tuple, which is 1, the function prints 1.
In the second call to test_func, the argument ([1, 2, 3, 4],) is passed, which is a tuple with a single element that is the list [1, 2, 3, 4]. This tuple is collected into the variable a, so a[0] corresponds to the first element of the tuple, which is the list [1, 2, 3, 4]. Therefore, the function prints [1, 2, 3, 4].
In the third call to test_func, the argument (1,) is passed, which is a tuple with a single element that is the integer 1. This tuple is collected into the variable a, so a[0] corresponds to the first element of the tuple, which is the integer 1. Therefore, the function prints 1.
Overall, the function test_func demonstrates the use of variable-length argument lists and tuple indexing in Python.
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