Question

What is the output of the following code?
dict 1={
dict 1["x"]=[5]
print (dict 1["x"][5])
a) 5
b) [5]
co
d) The code generates an error​

Answer 1

Answer:

d)The code generates an error

Explanation:

Because dict1 is initialised with only an opening curly brace..

If it was correct, even then the code produces an error because the key value is out of range