Question

What is the output of the following Python code?
int_list = [0, 1, 2, 3, 4, 5]
ch = 0
element = 0
while element is int_list[ch]:
print(element, end="")
ch = ch + 1
element = int_list[ch+1]
else:
print(int_list[element])​

Answer 1

Answer:

Output :-

0

1

2

3

4

5

I'm hoping this is the correct answer.

Answer 2

Answer:

The code prints the ultimate thing of int_list, which is 5.

Explanation:

The given Python code will end result in an error due to the fact there is an illegal persona at the quit of the ultimate line ().

Assuming that the unlawful persona is removed, the corrected code will output:

       01234

       5

Here's how the code works:

• int_list is a listing of integers from zero to 5.
• ch is an index variable that starts offevolved at 0.
• element is a variable that will save the cutting-edge thing of int_list.
• The whilst loop exams if the cutting-edge thing is equal to int_list[ch]. Since ch begins at zero and component is initialized to 0, the first generation of the loop will print 0.
• The ch variable is incremented to 1, and component is set to int_list[ch+1], which is equal to 2.
• The 2d new release of the loop tests if factor is equal to int_list[ch], which is false, so it jumps to the else block.
• The else block prints the cost of int_list[element], which is 2.
• The loop continues in this manner till it has printed all of the factors of int_list.
• Finally, the code prints the ultimate thing of int_list, which is 5.

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