what is the output of the program?
#include <iostream>
Answers
Answer:
#include <iostream>
using namespace std;
int arr[10] = {10, 11, 12, 13, 14, 15, 16, 17, 18, 19};
void swap(int p, int q)
{
int temp = arr[p];
arr[p] = arr[q];
arr[q] = temp;
return;
}
void printArr(int size)
{
int k;
for (k = 0; k < size; k++)
cout << arr[k] << " ";
cout << endl;
return;
}
void Permutation(int n, int size)
{
int k;
if (n == 0)
printArr(size);
else
{
for (k = n - 1; k >= 0; k--)
{
swap(k, n - 1);
Permutation(n - 1, size);
swap(k, n - 1);
}
}
return;
}
int main()
{
Permutation(3, 4);
return 0;
}
Explanation:
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Answer:
Question - 1. #include <stdio.h> int main() { int x; x = 10; if(x > 10) x -= 10; else if(x >= 0) x += 00; else if(x) x += 10; else x -= 10; printf("%d\n",x); return 0; } ... Question - 4. #include <stdio.h> int main() { int a=10,b=20,*p,s=0; p = &a; a++; (*p)++; s = a + b + *p; printf("%d\n",s); return 0; } ... Question - 5.
Explanation:
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