Question

What is the oxidation and coordination number of Co in
this [Co(en)2(H2O)CN]2+ complex ion Which ligand is bidentate in the above
complex?

Answer 1

Answer:

oxidation number of complex is 3

coordination number is 6

bidentate ligand is en (ethylene diammine)

Answer 2

Answer:

Ammonia, ethylenediamine, and EDTA are examples of monodentate, bidentate, and polydentate ligands, respectively.

Explanation:

The charge on the ion corresponds to the atom's oxidation number. The total of the oxidation numbers of the constituent atoms in a molecule or compound determines the oxidation number of that substance.

We have [Co(en)2 (H2 O)CN]2+, which contains 2 ethylenediamine (en)

Molecules, 1 $H_{2} O$ molecule and 1 CN atom attached with a central metal atom. The charge on en is 0, as it is a neutral ligand, the charge on the water is 0, the charge on CN is -1, and the charge on the complex is +2. For the central atom, we calculate the oxidation number as follows:  let us consider the oxidation number of Co is x.

.$x+2(0)+0+(-1)=+2\\x=+2+1\\x=3$

Therefore, the oxidation number of Co is +3. 

The coordination number of the metal atom or ion refers to the number of ligand atoms that are directly bound to the core metal atom or ion by the coordinate bond.

In this compound, the metal Co is directly linked to two ethylenediamine molecules, one water molecule, and one CN atom. Since it has two donor atoms, ethylenediamine acts as a bidentate ligand in this reaction. As a result, this complex's coordination number is 6.

Bidentate ligand: A ligand is referred to as a bidentate ligand if it has two donor atoms. Ethylenediamine (en), which has two donor atoms, is the bidentate ligand in the aforementioned complex. In this, the center metal ion can get electrons from both C and N.

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