Chemistry, asked by Arapot, 11 months ago

What is the oxidation and reduction in NaI(aq) + 3HOCl(aq) -> NaI3(aq) + 3HCl(aq) ?

Answers

Answered by ShreyaVirat
1

Answer:

HEY BUDDY...

GOOD NOON

OXIDATION - 3 HCl

REDUCTION - 3HOCl

HOPE IT HELPS !!!

HVE A GRT DAY AHEAD ^_^

Answered by roza15
2

Explanation:

NaI + 3HOCl = 3 HCl + NaIO3

now..

I^-1 -6e= I^+5 ( I goes -1 to +5 ) oxidation

3Cl^+1 + 6e = 3Cl^-1 ( Cl goes +1 to -1) reduction

hope it helps you ......

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