what is the oxidation no. of hydrogen in the reaction in both reactant side and product side
HCl + NaOH ----> NaCl + H2O
give correct answer
Answers
Explanation:
As usual, oxidation and reduction occur together. In this equation, both H2 and O2 are the molecular forms of their respective elements and therefore their oxidation states are 0. The product is H2O: the oxidation state is -2 for oxygen and +1 for hydrogen.
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Answer:
The correct answer is 2Na(s)+2H_2O(l)\rightarrow 2NaOH(aq.)+H_2(g)2Na(s)+2H2O(l)→2NaOH(aq.)+H2(g)
Explanation:
Oxidation number is defined as the number which is given to an atom when it looses or gains electron. When an atom looses electron, it attains a positive oxidation state. When an atom gains electron, it attains a negative oxidation state.
Oxidation state of the atoms in their elemental state is considered as 0. Hydrogen is present as gaseous state.
For the given chemical reactions:
Reaction 1: 2HClO_4(aq.)+CaCO_3(s)\rightarrow Ca(ClO_4)_2(aq.)+H_2O(l)+CO_2 (g)2HClO4(aq.)+CaCO3(s)→Ca(ClO4)2(aq.)+H2O(l)+CO2(g)
Oxidation state of hydrogen on reactant side: +1
Oxidation state of hydrogen on product side: +1
Thus, the oxidation state of hydrogen is not changing.
Reaction 2: CaO(s)+H_2O(l)\rightarrow Ca(OH)_2(s)CaO(s)+H2O(l)→Ca(OH)2(s)
Oxidation state of hydrogen on reactant side: +1
Oxidation state of hydrogen on product side: +1
Thus, the oxidation state of hydrogen is not changing.
Reaction 3: HCl(aq.)+NaOH(aq.)\rightarrow NaCl(aq.)+H_2O(l)HCl(aq.)+NaOH(aq.)→NaCl(aq.)+H2O(l)
Oxidation state of hydrogen on reactant side: +1
Oxidation state of hydrogen on product side: +1
Thus, the oxidation state of hydrogen is not changing.
Reaction 4: 2Na(s)+2H_2O(l)\rightarrow 2NaOH(aq.)+H_2(g)2Na(s)+2H2O(l)→2NaOH(aq.)+H2(g)
Oxidation state of hydrogen on reactant side: +1
Oxidation state of hydrogen on product side: 0
Thus, the oxidation state of hydrogen is changing.
Reaction 5: SO_2(g)+H_2O(l)\rightarrow H_2SO_3(aq.)SO2(g)+H2O(l)→H2SO3(aq.)
Oxidation state of hydrogen on reactant side: +1
Oxidation state of hydrogen on product side: +1
Thus, the oxidation state of hydrogen is not changing.
Hence, the correct answer is 2Na(s)+2H_2O(l)\rightarrow 2NaOH(aq.)+H_2(g)2Na(s)+2H2O(l)→2NaOH(aq.)+H2(g)