Question

what is the oxidation no of in xef6 each

Answer 1

Assuming you wanted to know the oxidation number of Xenon in XeF6,

XeF6 has zero net charge. And going by the position of F in periodic table, it's oxidation no will be -1.

So,

XeF6 = 0

Let charge of Xe be x.

x + 6(-1) = 0

x - 6 = 0

x = +6

So, we get oxidation no. of Xenon as +6.

Hope this helps.

Answer 2

The Oxidation Number of Fluorine is -1 respectively, as all Halogens have -1 as Ocidation number. Since, the net charge here is zero.
Therefore, Xe+(-1)❌6=0
Xe - 6=0
Xe= +6.

Hence Oxidation number of Xenon is +6.