what is the oxidation no. of S in H3SO2?
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H=+1
O=-2. let S=x
THEN
3(+1)+x+2(-2)=0
3+x-4=0
x=+1
hence oxidation no. of sulphur is +1
O=-2. let S=x
THEN
3(+1)+x+2(-2)=0
3+x-4=0
x=+1
hence oxidation no. of sulphur is +1
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