Question

What is the oxidation number Cr in Na2Cr2O7?

Answer 1

let oxidation number of cr be X

therefore 2+2x-(2×7)=0

implies 2x+2=14

implies 2x=12

implies X=+6

Thus oxidation number of chromium(Cr)is +6

Answer 2

The oxidation number Cr in Na2Cr2O7 is +6.

Explanation for the answer:

• The total number of electrons which an atom either gains or loses in order to form a chemical bond with some another atom is known as oxidation number.
• It is also called an Oxidation state.
• Here, we have to calculate the oxidation number Cr in Na2Cr2O7.
• Firstly, let the oxidation no. Cr be x.
• Therefore, 2 + 2x - (2 × 7) = 0
• $2 + 2x - (2 × 7) = 0$
• Therefore, $2x + 2 = 14$
• Thus, $x = 6$
• Hence, the oxidation no. Cr = +6.

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