Question

what is the oxidation number of 2ag in 2agbr​

Answer 1

Answer:

(a) 2AgBr (s) + C6H6O2(aq) → 2Ag(s) + 2HBr (aq) + C6H4O2(aq) (b) HCHO(l) + 2[Ag (NH3)2]+ (aq) + 3OH-(aq) → 2Ag(s) + HCOO–(aq) + 4NH3(aq) + 2H2O(l) (c) HCHO (l) + 2 Cu2+ (aq) + 5 OH–(aq) → Cu2O(s) + HCOO-(aq) + 3H2O(l) (d) N2H4(l) + 2H2O2(l) → N2(g) + 4H2O(l)

Answer 2

Answer:

Explanation:

Oxidised substance:- C6H6O2

Reduced Substance:-AgBr

Reducing agent:- C6H6O2

Oxidising agent:-AgBr

Explanation:- Oxidising agent is a reagent which can increase the O.N. of an element in a given substance.

Here, AgBr helps carbon in C6H6O2 to increase its oxidation number.

The reduced substance is a reagent whose oxidation state has been decreased.

Here, in this case, Ag in AgBr has + 1 oxidation state and the O.N. is reduced to zero as Ag in the product side is present in zero O.N. (its elemental form)

The oxidised substance is a reagent whose oxidation state has been decreased.

C in C6H6O2 has O.N. of -0.33 which is being increased to zero in C6H4O2

Reducing Agent is a reagent which lowers the oxidation number of an element in a given substance.

C6H6O2 helps Ag of AgBr to decrease its oxidation state