Chemistry, asked by syedanoor12, 1 year ago

WHAT IS THE OXIDATION NUMBER OF C IN C6H12O4

Answers

Answered by Anonymous

-2/3.......................

Answered by Wahida05

The O.N of C in glucose is +4

syedanoor12: NOT IN GUCOSE

syedanoor12: GLUCOSE

Wahida05: Oh i think -2 is the o. n of C6H12O4

syedanoor12: PLZ SOLVE IT FOR ME??

Wahida05: ok I'll try

syedanoor12: THNKS

syedanoor12: BUT I WNT IT NOW

Wahida05: -0.671

syedanoor12: ITX WRONG I THNK

Wahida05: The O.N of C in C6H12O4 Let the O.N. of C be x.
We know that, O.N. of H and O are 1 and -2 respectively.
Therefore, 6x + 12(1) + 4(-2) = 0
(because C6H12O4 is neutral i.e. it has no charge on it)
6x + 12 - 8 = 0
6x + 4 = 0
6x = -4
x = -4/6 = -2/3
x = -0.66

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