Question

What is the oxidation number of Cr in Cr,2 O2-7
?​

Answer 1

Answer:

$cr2o7 = 0$

$oxidation \: state \: of \: o \: = - 2$

put

$- 2 = o$

$cr2 = 14$

cr

$= 7$

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Answer 2

There are seven oxygen atoms, so the total charge is −2⋅7=−14 . So, two chromium atoms have a total oxidation number of +12 . Since one is not more electronegative than the other, we can divide the number by two to get one chromium's oxidation number.