Question

what is the oxidation number of Cr(NO3)3 ?? step wise..​

Answer 1

Answer:

Explanation:

NO3- is the nitrate ion, since the overall charge of the anion is -1, you don't need to worry about the O's and the N's as they are unimportant. So since there are three nitrate anions, their total oxidation number is -1 x 3 = -3 so it makes sense that the O.N of the chromium is...

Answer 2

The oxidation number of chromium in $Cr(NO_3)_3$ is +3.

Explanation:

Oxidation number is defined as the number holded by an atom by either gain or loss of electrons when it chemically combines with another atom.

As in $Cr(NO_{3})_{3}$ compound we know that the oxidation number of nitrate ion is -1. So, for three nitrate ions the charge will be -3.

Let us assume that the charge on chromium (Cr) is x. Therefore, calculate the oxidation number of chromium as follows.

                      $Cr(NO_{3})_{3}$

                    $x + 3 \times (-1) = 0$   (as the compound is neutral so its total charge is equal to zero)

                         x - 3 = 0

                          x = +3

Therefore, the charge present on chromium atom is +3.

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