Question

what is the oxidation number of Cu in Cu(NO3)2.

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Answer 1

The Cu(NO3)2 is an ionic compound with oxidation number “0”. Therefore we know that sum of all the oxidation number of Cu, N and O is equal to 0.

1) the charges of the elements since it is an ionic bond. Cu=+2, N=+5, O=-2.
Simply add the numbers based on the formula:

0= +2 (2(+5) + 2×3(-2))

0= +2 (+ 10 - 12)

0=0

The above proves that the charges of the elements in the ionic bond is equal to Cu=+2, N=+5, O=-2
therefore,it is the oxidation number.

Answer 2

Answer:

The oxidation state of copper in Cu(NO₃)₂ is +2.

Explanation:

The oxidation number of an atom in a given compound is calculated as follows.

• Write the oxidation state above its atoms.
• Write x above the atom for which the oxidation state has to be calculated.
• Multiply the oxidation number of each element with the number of atoms of the element present in the compound.
• Equate the algebraic sum of the oxidation number of all atoms present in a compound to zero and present in an ion to the charge on the ion.
• Solve the equation for getting the value of x.

The oxidation number of Cu in Cu(NO₃)₂

The oxidation state of nitrate is -1.

Thus, x + (-1×2) = 0

x -2 = 0

x = +2

The oxidation state of copper in Cu(NO₃)₂ is +2.

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