What is the oxidation number of fe in K3[Fe(CN)6]
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k=1 CN=-1 then 1 x 3 + Fe + 6 x -1=0
3 + Fe + -6 =0
Fe=-3
Explanation:so the charge of k is 1 and the charge of CN is -1 and thus from the formula we have K3 then multiply it by its charge which is 1 and then for CN we have (CN)6 then you multiply it by its charge which is -1 and then add them to get the coordination number of Fe
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