Question

What is the oxidation number of I in NaIO3?

Answer 1

Oxidation number refer to the change that an atom in a compound holds when a compound is completely or fully ionic. Oxidation number determining a set of simple rules by which they can be reached at. The Oxidation number of Iodine in NalO3 is +5.

Answer 2

The oxidation number of I in $NaIO_3$ is +5

Explanation:

Rules for Oxidation Numbers :

1. The oxidation number of a free element is always zero.
2. The oxidation number of a monatomic ion equals the charge of the ion.
3. The oxidation number of  Hydrogen (H)  is +1, but it is -1 in when combined with less electronegative elements.
4. The oxidation number of  oxygen (O)  in compounds is usually -2, but it is -1 in peroxides.
5. The sum of the oxidation numbers in a polyatomic ion is equal to the charge of the ion.

The given compound is $NaIO_3$

Let the oxidation state of I be, 'x'

$1(+1)+1(x)+3(-2)=0$

$x=+5$

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