What is the oxidation number of K3[Fe(CN)5CO]
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3+ x-5 =0
x= 5-3
x =2
Fe2+
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1
Answer:
Explanation:
Oxidation number of (CN)5is(- 1)×5
Oxidation number of K3 is 1×3 and that of CO is 0
3+ x-5 =0
x= 5-3
x =2
Fe2+
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