what is the oxidation number of l in HOl
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Answer:
=1+(-2)+x
=-1+x
x=1
hence oxidation number of I is 1
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The oxidation number of iodine in HOI is +1.
Explanation:
- Oxidation number of an atom in the compound is the imaginary oxidation state of the atom in the compound assuming the compound to be fully ionic.
- The oxidation number of the atom in the compound is calculated by means of simple arithmetic.
- The oxidation number of hydrogen is +1.
- The oxidation number of oxygen is - 2.
- So the oxidation number of iodine is +1.
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