Question

What is the oxidation number of N in NH4F

Answer 1

Answer:

answer is x+4-1=0

x=-3

Answer 2

Answer:

The oxidation number of nitrogen atom in $NH_{4} F$ is -3.

Explanation:

Given the molecule, $NH_{4} F$

Oxidation number of an atom is the number of electrons that an atom has either gained or lost in bonding with the other atom.

The sum of oxidation numbers in a neutral compound is 0.

The oxidation number of fluorine is always –1  and hydrogen is +1.

Let the oxidation number of nitrogen atom in $NH_{4} F$ be x.

$x+(4\times 1)+(-1)=0$

$x+4-1=0$

$\implies x=1-4= -3$

Hence the oxidation number of nitrogen atom is -3.