What is the oxidation number of (NH4)2So4
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Explanation:
The total charge on sulphate ion is -2 , hence the total charge on ammonium ion (NH4)2 should be +2. Total charge on a single ammonium ion (NH4) is +1.
Hence the required equation will be
x+4*(1) = +1
Solving the equation will give the oxidation state of nitrogen - 3 and not 1.
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Explanation:
(NH 4 ) 2SO 4⇌2NH 4+SO 4 2−
N H 4+
Let, x be the oxidation state of N.
x+4×1=+1; ⇒x=−3
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