Question

What is the oxidation number of nickel in tetracarbonyl nickel??

Answer 1

Answer:

In nickel tetracarbonyl, the oxidation state for nickel is assigned as zero. The formula conforms to 18-electron rule. The molecule is tetrahedral, with four carbonyl (carbon monoxide) ligands attached to nickel.

Explanation:

Answer 2

Given that,

The oxidation number of nickel in tetracarbonyl nickel.

We know that,

Tetracarbonyl nickel :

The chemical formula of Tetracarbonyl nickel is $Ni(CO)_{4}$.

Let x be the oxidation number of of Ni in $Ni(CO)_{4}$.

The charge on the complex is 0.

The sum of oxidation numbers of all elements is zero.

We need to calculate the oxidation number of nickel in tetracarbonyl nickel

Using formula of oxidation

$x+4(q)=0$

Where, x = The oxidation number of of Ni

q = the charge on the complex

Put the value into the formula

$x+4(0)=0$

$x+4\times0=0$

$x=0$

Hence, The oxidation number for nickel is zero in tetracarbonyl nickel.