Question

What is the oxidation number of O3 in 2NaS2O3 ? Please explain in detail .
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Answer 1

let the oxidation number of O3 be x
then, (+1) + 2(+2) + 3x = 0
=> 1 + 4 + 3x = 0
=> 3x = -5
=> x = -5/3

Therefore, the oxidation number of O is -5/3 which is actually the average oxidation number since oxidation number cannot be in fractions it has to be in whole numbers only. Hence, -5/3 is just the average oxidation number of O

Hope it helps...

Disclaimer: This is my own thinking, and i have not copied this Answer from any book or website and that's why i cannot guarantee its authenticity.
If even a small mistake is found in the above answer i am not responsible for it whatsoever.

Thanking You

Answer 2

Answer:the oxidation number of o3 in 2NaS2O3 is +1.

Explanation:

for Nas2o3, how much compound we are taking has no impact on oxidation number of an element .so mentioning 2 in NaS2O3 is not necessary.

the answer is as follows,

NA+2(S)+3(O)=0

1+2(-2)+3(x)=0

1-4+3x=0

-3+3x=0

3x=3

x= +1

here mentioning the sign whether it is positive or negative is important.