what is the oxidation number of oxygen in different cases, explain clearly
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hi friend...
the oxidation of oxygen in.different compounds is -2 except for peroxides like H2O2,Na2O2 ,in which the oxidation of oxygen is -1
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the oxidation of oxygen in.different compounds is -2 except for peroxides like H2O2,Na2O2 ,in which the oxidation of oxygen is -1
I hope this will help u ;)
PLZZ mark it as the BRAINLIEST....
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The oxidation number for an atom of any free elements is zero the atoms in H2,O2,Fe, CI2, and An have zero oxidation numbers
The oxidation number for any simple one atom ion is equal to it's charge thus the oxidation number of Na^+ is + 1 ; of Ca^2+,+2; and if CI - ,-1.
The oxidation number of oxygen is --2 in all compound in which oxygen does not form an O -- O covalent bond. Thus, it's oxidation number is --2 in H2O, H2SO4,NO, CO2 ,and CH3OH, but in hydrogen peroxide, H2O2 ,it is --1
The oxidation number for any simple one atom ion is equal to it's charge thus the oxidation number of Na^+ is + 1 ; of Ca^2+,+2; and if CI - ,-1.
The oxidation number of oxygen is --2 in all compound in which oxygen does not form an O -- O covalent bond. Thus, it's oxidation number is --2 in H2O, H2SO4,NO, CO2 ,and CH3OH, but in hydrogen peroxide, H2O2 ,it is --1
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