Chemistry, asked by Mayurdhvajsinh, 1 year ago

What is the oxidation number of Oxygen(O) in Potassium Ozonide?

Answers

Answered by mihirsthacker
5

Oxygen has an oxidation state of −2 except where it is

−1 in peroxides,

−1/2 in superoxides,

−1/3 in ozonides,

and of +2 in oxygen difluoride,


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Answered by Anonymous
2

Explanation:

Oxidation number is the charge left on the atom of interest, when all the bonding electrons are removed with the charge devolved to the more electronegative atom.

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