Question

what is the oxidation number of pbso4​

Answer 1

Answer:

PbSO4→Pb2+[SO4]2−

Let the oxidation state of S be x

The oxidation state of O is -2

Therefore, for [SO4]2−⇒x+4(−2)=−2

∴x−8=−2

∴x=+6

Therefore, the oxidation number of S in PbSO4 is +6.