what
is the
oxidation
number of
Phosphorus in Pou4
Answers
Answered by
0
x=oxidation number of P= +3. Hydrogen and oxygen have oxidation numbers of +1 and -2. The ion has a charge of -1, so the sum of the oxidation numbers must be -1. Letting y be the oxidation number of phosphorus, -1= y + 2(+1) +4(-2), y= oxidation number of P= +5.
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Answered by
0
Answer:
Oxidation of Phosphorus in PO4 = 5
Explanation:
The oxidation state of P in PO4 can be calculated as under.
PO4 has 3- charge on it.
Lets suppose that charge on P is x. Also the charge on oxygen is -2.
So form a linear equation.
x + 4(-2) = -3
x-8=-3
x=-3+8
x= 5.
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