Question

what is the oxidation number of S in FeSO4.7H2O

Answer 1

Answer:

+2

Explanation:

to form stable compound the net charge on FeSO4 must equal to zero.

So ,

1*(o.s. of Fe)+1*(o.s. of S)+4*(o.s. of O)=0

1*(o.s. of Fe)+1(+6)+4(-2)=0

(O.s. of Fe) +6–8=0

O.s. of Fe =8–6

O.s.of Fe=+2.

Hence oxidation state /oxidation number of Fe in FeSO4 is +2