what is the oxidation number of s in h2s
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In the compound hydrogen sulfide, H2S, the two hydrogen atoms have an oxidation number of +1, for a total of +2. Therefore, the oxidation number of sulfur in the compound is -2, and the sum of the oxidation numbers is 0.
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In the compound hydrogen sulfide, H2S, the two hydrogen atoms have an oxidation number of +1, for a total of +2. Therefore, the oxidation number of sulfur in the compound is -2, and the sum of the oxidation numbers is 0.
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Answered by
19
Given compound -

Oxidation Number of H = + 1
Let the oxidation number of S be x.
•°•
x + 2 ( + 1 ) = 0
x + 2 = 0
x = - 2
Hence, Oxidation number of S = - 2
^^"
Oxidation Number of H = + 1
Let the oxidation number of S be x.
•°•
x + 2 ( + 1 ) = 0
x + 2 = 0
x = - 2
Hence, Oxidation number of S = - 2
^^"
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