Question

what is the oxidation number of S in Na2S4O6 and Na2SO3 ?​

Answer 1

Answer:

Explanation: It is known that oxidation state of sodium is +1, so oxidation state for two sodium atoms will be +2.

Answer 2

Answer:

• The oxidation state of Na here is +1, and the oxidation state of O is -2. We multiply these oxidation states with the number of molecules of that element in the compound. We take the unknown oxidation state as x.  2∗1+4∗x+6∗−2=0    Solving for x, we get the oxidation state of sulphur to be 2.5.   The reason for this is that within the molecule, different sulphur atoms have different oxidation states.

• Let the oxidation no. of S is x  Then,(+1)×2 +x×4 + (-2)×6 = 0  or,+2+4x-12=0  or, 4x -10=0  or, x = 10/4 = +2.5

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