Chemistry, asked by harshnaveen8135, 8 months ago

What is the oxidation number of S in (NH4)2S2O8

Answers

Answered by paypayrod8

Answer:

Explanation:

S₂ has the oxidation number of 0 due to one of the rules for assigning oxidation numbers. This rule states that the oxidation number of an element in it's free or uncombined state is zero. Other examples of this would be H₂, N₂, Fe, etc. Hope this helped :)

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