Question

What is the oxidation number of sulfur in the HSO4- ion?

Answer 1

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Answer 2

Concept:

The total number of electrons that an atom gains or loses in order to form a chemical connection with another atom is known as the oxidation number.

Given:

$HSO_{4}^{-}$

Find:

The oxidation number of sulfur in the $HSO_{4}^{-}$ ion is?

Solution:

Let the oxidation number of sulfur in $HSO_{4}^{-}$ be x.

The oxidation number of hydrogen is +1.

The oxidation number of oxygen is -2.

The overall charge on the ion is -1.

Thus, we can calculate the oxidation state of sulfur in $HSO_{4}^{-}$ is as follows below:

                           The oxidation number of ( S + 4*O + H) = Overall charge

                                             x + 4/(-2) + 1 = -1

                                                    x - 8 + 1 = -1

                                                         x - 7 = -1  

                                                              x = -1 + 7

                                                              x = +6

Therefore, the value of x comes out to be +6.

Hence, the oxidation number of sulfur in the $HSO_{4}^{-}$ ion is +6.

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