Question

what is the oxidation number of sulphur in ferric sulphate and ferrous sulphate

Answer 1

Ferric Sulphate Fe2(SO4)3=Fe2S3O12 Oxidation no. of iron is 3 & oxygen is -2 So, Fe charge =2*3=6 O charge=12*-2=-24 Fe+O=6-24=-18 To make charge 0, -18+S3=0 => S3=18 S=6 Ferrous Sulphte, FeSO4 Oxidation no. og Fe is 2 and of O is -2 So, Fe charge=2 O charge=4*-2=-8 F+O=2-8=-6 As in ferric sulphate -6+S=0 S=6