what is the oxidation number of sulphur in H2S 05
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Answer:
+6
Explanation:
There are two peroxide groups in the compound with oxidation state -1 hence equation can be split up as
H2SO3^(-2)O2^(-1)
Therefore
(+2)+x+3(-2)+2(-1)=0
2-6-2+x=0
x=+6
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