what is the oxidation number of sulphur in s2o82-
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S2O8 (2-)
charge O: 8 * (-2) = -16
Charge of S: 2s - 16 = -2
2s = 14
s = 14/2 = 7
S2O8 (2-)
charge O: 8 * (-2) = -16
Charge of S: 2s - 16 = -2
2s = 14
s = 14/2 = 7
rohit131427:
sorry ...... i too got the sam eanswer but that isn't the answer for sure
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