Question

what is the oxidation number of the Nitrogen in the compound n2o4

Answer 1

Answer:

....Hope it helps buddy...

Answer 2

Answer:

Explanation:

Firstly,we should know,What is oxidation number.

So,

OXIDATION NUMBER:

             Oxidation number is the apparent charge on

             the atom of the element in combined form.

Example:

In SO2,the charge on sulphur will be +4

How is it?

As we know, Oxygen has -2 charge.

In SO2,there are 2 atoms of oxygen.

So,Charge on two atoms of oxygen is -4

As the molecule is overall neutral.So,there should be +4 charge on sulphur.

Oxidation number of nitrogen in N2O4:

Oxidation number of single atom of oxygen is -2

Oxidation number of 4 atoms of oxygen = -2(4)

                                                                   =-8

As the molecule is overall neutral,so,there will be +8 charge on N2

So,charge on single atom of nitrogen is +4

HAVE A GREAT DAY MATE :)