What is the oxidation state of C and N in HCN and HNC respect ively? explain.
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Answered by
139
HCN --
let O.N. of C is x
so 1+ x -3 =0
O.N. of C = x= + 2
that of N = - 3
----------------------------------
HNC ----------
1+ x-5 = 0
x = 4
O.N,. of C = +4
ON. of N = -5
or
oxidation
number of C
and N in HCN, HCN.. O.N of H=+1,O.N of C=? , O.N of N=-3. HCN 1+x+(-3)=0. 1+x-3=0. x-2=0 x=+2.Therefore,the oxidation of Carbon is -3. <2>: oxidation
number of C
and N in HNC
O.N of H=1,O.N of Carbon=+2,O.N of Nitrogen=? HNC 1+x+2=0. x+3=0. x=-3. Therefore,the oxidation number of Nitrogen is -3. You can now see that it is the oxidation number is the same with the no1. HCN and HNC are the same, it was just rearranged and displaced from it's normal position.
let O.N. of C is x
so 1+ x -3 =0
O.N. of C = x= + 2
that of N = - 3
----------------------------------
HNC ----------
1+ x-5 = 0
x = 4
O.N,. of C = +4
ON. of N = -5
or
oxidation
number of C
and N in HCN, HCN.. O.N of H=+1,O.N of C=? , O.N of N=-3. HCN 1+x+(-3)=0. 1+x-3=0. x-2=0 x=+2.Therefore,the oxidation of Carbon is -3. <2>: oxidation
number of C
and N in HNC
O.N of H=1,O.N of Carbon=+2,O.N of Nitrogen=? HNC 1+x+2=0. x+3=0. x=-3. Therefore,the oxidation number of Nitrogen is -3. You can now see that it is the oxidation number is the same with the no1. HCN and HNC are the same, it was just rearranged and displaced from it's normal position.
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