Question

What is the oxidation state of carbon in c6h6o2

Answer 1

The oxidation state of carbon is

6X + 6 + 2 (-2) = 0
therefore

6X + 2 = 0
6x = -2
X = -2/6
X = -1/3....

thus x is the oxidatio state of carbon....

Answer 2

The Oxidation State of Carbon in $C_6H_6O_2$ is -0.33.

Explanation:

• The given compound, $C_6H_6O_2$ is a hydro-carbon and is known as Resorcinol.

• It is also referred to as Benzene-1,3-diol and its weight is 110 grams.

• It is a solid of white colour which will usually change its colour to pink when it will be exposed to the air, the light and even the iron.

• As the given compound is a Hydro-Carbon we can easily find the Oxidation state of the Carbon atom using a short trick.

• The oxidation state of carbon in hydro-carbon is equal to the ratio of difference between two times of the oxygen atoms present in the molecule and the number of hydrogen atoms to the number of carbon atoms.

• The formula is:

• oxidation number of $C= \frac{2 \times n u m b e r \text { of } o^{\prime} s-n u m b e r, o f H}{\text { no of } c}.$

• So by substituting the number of atoms in the hydrocarbon, we get the answer as

         $\frac {-2}{6}$ which is equal to -0.33.

Learn more about oxidation state

Why is the + 2 oxidation state of Mn (25) is quite stable, while the same is not true for iron (26)?

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Discuss the pattern of variation in the oxidation states of

(i) B to Tl and

(ii) C to Pb.

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