Question

what is the oxidation state of Fe in the brown ring complex [Fe(H2O)5NO]SO4

Answer 1

From the compound [Fe (H2O)5NO]SO4

• Oxidation state of Iron or "Fe" in the brown ring is influenced by its binding mode on the NO ligands (linear or bent)

• The five molecules of water present in the equation are neutral, while NO is a Mono Dendate Anionic Ligand

• The Sulphate (SO4) is a divalent ion, while the Fe is present in its Ferric ion Considering this, X + 5 (0) + 1 (-1) + 1 (-2) = 0 where X = +3 Thus, the oxidation state of Fe in the given equation is +3.

Answer 2

NO here exist as +1 , so Oxidation no. of Fe is +1

+2=1+5×0+x

+2=1+x

so, x=+1