Question

what is the oxidation state of iodine in KIO4 molecule?​

Answer 1

Answer:

+7

Explanation:

+7

The sum of the oxidation numbers in a polyatomic ion is equal to the charge on the ion. The charge on this polyatomic ion is 0. To get the oxidation number of I, we will let x as the oxidation number of I. Therefore, the oxidation number of iodine atom in KIO4 is +7.

Answer 2

The oxidation state of iodine in $KIO_{4}$ molecule is +7.

Explanation:

The number obtained by an atom due to gain or loss or electrons is known as oxidation number. For example, in the molecule $KIO_{4}$ we assume that the oxidation number of iodine is x.

Oxidation number of potassium is +1 and oxygen is -2. Hence, we will find out the oxidation number of iodine as follows.

          1 + x + 4(-2) = 0      (as the molecule is neutral so total charge is 0)

          1 + x -8 = 0

             x = +7

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