What is the oxidation state of K in KO2
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Answered by
149
In kO2 oxidation state of each oxygen is -1/2.
let oxidation state of k in KO2 be x
x+2(-1/2)=0
x=+1
hence, oxidation state of k is +1
let oxidation state of k in KO2 be x
x+2(-1/2)=0
x=+1
hence, oxidation state of k is +1
Answered by
45
K i.e. pottSium is a member of group 1 so it readily reacts with oxygen.
As we move down the group the tendency of forming peroxides and super oxides increase. KO2 is pottasium super oxide ko2 =k+ + O2( 1-) .
O2 (1-) is super oxide in which o has a charge of -1/2.
ko2 =+1×1 + x (oxidation state of oxygen )×2=0 (as ko2 is electrically neutral)
On solving
1+2x=0
=> x= -1/2
rwjni:
Very nice explanation
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