Question

what is the oxidation state of phosphorus in NaH2PO2?

Answer 1

NaH2PO2

Na+2(H)+P+2(O)=0
1+2(1)+P+2(-2)=0
1+2+P-4=0
P+3-4=0
P-1=0
P=1

The oxidation state of Phosphorus is +1

hope it helps

Answer 2

The oxidation state of phosphorus in NaH2PO2 is given as :-

Na+2(H)+P+2(O)=0 (Arranging elements according to there molecules)

1+2(1)+P+2(-2)=0 (Placing oxidation state other other than Na)
1+2+P-4=0
P+3-4=0
⇒P=1

so the oxidation state of phosphorus in NaH2PO2 is +1

Hope it will help u.
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