what is the oxidation state of phosphorus in NaH2PO2?
Answers
Answered by
106
Let oxidation state(os)of P is NaH2PO2 be x
os of oxygen is -2
os of Na is +1
os of hydrogen is +1
Total os of a molecule is zero (if neutral).
so by adding os we get
(+1)+(+1×2)+(x)+-2×2)=0
or
x=+1
So oxidation state of phosphorus in NaH2PO2 is +1
os of oxygen is -2
os of Na is +1
os of hydrogen is +1
Total os of a molecule is zero (if neutral).
so by adding os we get
(+1)+(+1×2)+(x)+-2×2)=0
or
x=+1
So oxidation state of phosphorus in NaH2PO2 is +1
Answered by
13
Answer:
oxidation state of P in NaH2PO2 is +1
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