what is the oxidation state of phosphorus in product after complete hydrolysis of P4O10?
Answers
Answered by
0
ANSWER
Oxidation number of oxygen in these compounds is -2. So we can find oxidation number of phosphorus.
In PO43−,x+4(−2)=−3,x=+5
In P4O10,4(x)+10(−2)=0,x=+5
In P2O7−2,2(x)+7(−2)=−4,x=+5
Oxidation number of oxygen in these compounds is -2. So we can find oxidation number of phosphorus.
In PO43−,x+4(−2)=−3,x=+5
In P4O10,4(x)+10(−2)=0,x=+5
In P2O7−2,2(x)+7(−2)=−4,x=+5
Answered by
0
Answer:
Explanation:
pls find the attachment
Attachments:
Similar questions