Question

what is the oxidation state of S in H2S2O6​

Answer 1

Given: Given a compound is $H_2S_2O_6$.

To find: We have to find the oxidation state of S.

Solution:

The given compound is $H_2S_2O_6$.

The charge of one hydrogen atom is +1 and the charge of one oxygen atom is -2.

Let the oxidation state of S be x.

The compound is neutral so the overall oxidation state of the compound is zero.

So, we can write-

$2x + 2 - 12 = 0 \\ 2x = 10 \\ x = + 5$

The value of x is +5.

Thus we can say that the oxidation state of a Sulfur atom is +5.