Question

what is the oxidation state of S in NaSCN

Answer 1

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Answer 2

The oxidation state of sulphur in NaSCN is -2.

Explanation:

• The oxidation state is the number ofelectrons, an atom lose or gain to attain a stable form by completing its octet.
• The oxidation number of sodium is +1 as it is a metal of IA group and has a valency of 1.
• the O.S of carbon is +4 and that of nitrogen is -3.
• Therefore, the oxidation state can be calculated as:

        Na+S+CN=0

        1+S+4-3=0

        S+2=0

        S= -2

• The oxidation state (O.S) of sulphur in sodium thiocyanide is -2.