what is the oxidation state of S2 in S2 O^-2 6
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If x is the oxidation state of S, then...
2x + (-2) × 6 = -2
2x = 10
x = +5
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Let x be the oxidation state of S in S2O62−.
Since the overall charge on the complex is −2, the sum of oxidation states of all elements in it should be equal to −2.
2x+6(−2)=−2
x=+5
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